std::declare_no_pointers

 

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智能指针 unique_ptr (C++11) shared_ptr (C++11) weak_ptr (C++11) auto_ptr (C++17 前*) owner_less (C++11) owner_less<void> (C++17) enable_shared_from_this (C++11) bad_weak_ptr (C++11) default_delete (C++11) out_ptr_t (C++23) inout_ptr_t (C++23) 低层内存管理 operator new operator new[] operator delete operator delete[] get_new_handler set_new_handler launder (C++17) bad_alloc bad_array_new_length nothrow_t align_val_t destroying_delete_t new_handler nothrow 杂项 pointer_traits (C++11) to_address (C++20) addressof (C++11) align (C++11) assume_aligned (C++20) C 库 malloc calloc realloc    aligned_alloc (C++17) free

 

在标头 <memory> 定义
void declare_no_pointers( char *p, std::size_t n );		(C++11 起) (C++23 中移除)

告诉垃圾收集器或泄漏检测器，指定的内存区域（从 p 所指向的字节开始的 n 个字节）不含可追踪指针。若区域的任何部分在分配的对象内，则同一对象中必须含有整个区域。

参数

p	-	指向范围起始的指针
n	-	范围中的字节数

返回值

（无）

异常

不抛出。

参阅

undeclare_no_pointers (C++11)(C++23 中移除)

取消 std::declare_no_pointers 的效果 (函数)